document.write( "Question 1147617: . At PrintAll copying, a new copying machine can produce five more than twice the number of copies per hour of the old copy machine. If the new machine produces 205 copies per hour, how many copies can the old machine produce? \r
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Algebra.Com's Answer #768957 by ikleyn(52866) You can put this solution on YOUR website! . \n" ); document.write( " \r\n" ); document.write( "\r\n" ); document.write( "Let \"x\" = \"how many copies can the old machine produce\", i.e. the number under the question.\r\n" ); document.write( "\r\n" ); document.write( "\r\n" ); document.write( "Then the new machine can produce 2x+5 copies, according to the condition.\r\n" ); document.write( "\r\n" ); document.write( "\r\n" ); document.write( "You are given\r\n" ); document.write( "\r\n" ); document.write( "\r\n" ); document.write( " 2x + 5 = 205.\r\n" ); document.write( "\r\n" ); document.write( "\r\n" ); document.write( "Hence, 2x = 205 - 5 = 200 and x = 200/2 = 100.\r\n" ); document.write( "\r\n" ); document.write( "\r\n" ); document.write( "ANSWER. The old copy machine can produce 100 copies per hour.\r\n" ); document.write( "\r \n" ); document.write( "\n" ); document.write( "Solved.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \r \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |