document.write( "Question 1147615: The equation for line j can be written as y=2x + 8. Another like k is perpendicular to line j and passes through the point (6,-6). Choose the equation for like k\r
\n" ); document.write( "\n" ); document.write( "A. Y= 1/2x-3
\n" ); document.write( "B. Y= -1/2x-3
\n" ); document.write( "C. Y=-2x-3
\n" ); document.write( "D. Y=-3/2x + 3
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Algebra.Com's Answer #768953 by Theo(13342)\"\" \"About 
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formula for line j is y = 2x + 8
\n" ); document.write( "line k is perpendicular to line j.
\n" ); document.write( "it will therefore have a slope that is a negative reciprocal to the slope of line j.
\n" ); document.write( "the general formula for line k is therefore y = -1/2 * x + b
\n" ); document.write( "since line k passes through the point (6,-6), then use that point to find the value of b.
\n" ); document.write( "replace x with 6 and y with -6 in the equation of y = -1/2 * x + b to get:
\n" ); document.write( "-6 = -1/2 * 6 + b
\n" ); document.write( "simplify to get:
\n" ); document.write( "-6 = -3 + b
\n" ); document.write( "solve for b to get:
\n" ); document.write( "b = -6 + 3 = -3
\n" ); document.write( "the equation of line k is therefore y = -1/2 * x - 3
\n" ); document.write( "here's the graph.you can see that the point (6,-6) is on that line, as well as see that the lines do indeed look perpendicular to each other.
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\n" ); document.write( "line j is the red line.
\n" ); document.write( "line k is the blue line.
\n" ); document.write( "y-intercept for line j is 8, as it should be.
\n" ); document.write( "y-intercept for line k is -3, as it should be.
\n" ); document.write( "intersection of line j and k is at the point (-4.4,-.8)
\n" ); document.write( "line k passes through the point (6,-6), as it should.\r
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