document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=105716>Question 105716</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Richards age in 11 years will be three times what it was 15 years ago. How old is Richard now?  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #76893 by </B><A HREF=/tutors/aboutme.mpl?userid=fmo><B>fmo(8)</B></A><img src=\"/images/stars/stars-05.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=fmo><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=76893\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Let's let x represent Richard's age.<BR>\n" );
document.write( "Richard's age in 11 years, can then be represented as x + 11.<BR>\n" );
document.write( "15 years ago, Richard's age would have been x - 15.<BR>\n" );
document.write( "Finally, we know that Richard's age in 11 years (x + 11) will be three times what it was 15 years ago (3 * (x - 15)), and that forms an equation that looks like:\r<BR>\n" );
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document.write( "x + 11 = 3 * (x - 15)\r<BR>\n" );
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document.write( "Now to solve... <BR>\n" );
document.write( "x + 11 = 3(x - 15)  (problem restated)<BR>\n" );
document.write( "x + 11 = 3x - 45    (right side expanded)<BR>\n" );
document.write( "    11 = 2x - 45    (subtract x from both sides)<BR>\n" );
document.write( "    56 = 2x         (add 45 to both sides)<BR>\n" );
document.write( "    28 = x          (divide both sides by 2)\r<BR>\n" );
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document.write( "Richard is 28 years old. </SPAN>\n" );
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