document.write( "Question 1147423: In △ABC, AC = BC, AB = 6, m∠BAC = 71º. Find the length of the altitude
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Algebra.Com's Answer #768896 by ikleyn(52788) $\"\"$ $\"About$

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document.write( "Given triangle ABC is isosceles; therefore, the altitude AH is the median, at same time.\r\n" );
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document.write( "It means that  AH = BH = 6/2 = 3 units of length.\r\n" );
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document.write( "Then  tan(A) = ,   or\r\n" );
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document.write( "      tan(71°) = ,\r\n" );
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document.write( "which implies  | AH | = 3*tan(71°).      ANSWER\r\n" );
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\n" ); document.write( "\n" ); document.write( "Be aware : the solution by @josgarithmetic giving the answer $\"AH%2Fsin%2871%29=6%2Fsin%2890%29\"$ is I N C O R R E C T (!)\r
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\n" ); document.write( "\n" ); document.write( "I came to bring the correct solution.\r
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