document.write( "Question 1147557: Using suitable substitutions solve for x, 2e^x=7√e^x -3 \n" ); document.write( "

Algebra.Com's Answer #768894 by greenestamps(13200) $\"\"$ $\"About$

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\n" ); document.write( "Let $\"u+=+e%5E%28sqrt%28x%29%29\"$

\n" ); document.write( "Then the equation is

\n" ); document.write( " $\"2u%5E2+=+7u-3\"$
\n" ); document.write( " $\"2u%5E2-7u%2B3+=+0\"$
\n" ); document.write( " $\"%282u-1%29%28u-3%29+=+0\"$

\n" ); document.write( " $\"u+=+1%2F2\"$ or $\"u+=+3\"$

\n" ); document.write( "(1) $\"e%5E%28sqrt%28x%29%29+=+1%2F2\"$
\n" ); document.write( " $\"e%5Ex+=+1%2F4\"$
\n" ); document.write( " $\"x+=+ln%281%2F4%29\"$

\n" ); document.write( "(2) $\"e%5E%28sqrt%28x%29%29+=+3\"$
\n" ); document.write( " $\"e%5Ex+=+9\"$
\n" ); document.write( " $\"x+=+ln%289%29\"$

\n" ); document.write( " \n" ); document.write( "

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