document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1147498>Question 1147498</A>: <I><SPAN STYLE=\"word-break: break-all;\"> <1 is supplemetary to <2<BR>\n" );
document.write( " <1 = 5x - 2y<BR>\n" );
document.write( "<2 = 20  + x<BR>\n" );
document.write( "find y in terms of x<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #768822 by </B><A HREF=/tutors/aboutme.mpl?userid=Theo><B>Theo(13342)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Theo><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Theo><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=768822\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> if the angles are supplementary, then their sum is 180 degrees.<BR>\n" );
document.write( "you get 5x - 2y + 20 + x = 180<BR>\n" );
document.write( "combine like terms to get 6x - 2y + 20 = 180<BR>\n" );
document.write( "subtract 20 from both sides of this equation to get 6x - 2y = 160<BR>\n" );
document.write( "add 2y to both sides of this equation and subtract 160 from both sides of this equation to get 6x - 160 = 2y<BR>\n" );
document.write( "divide both sides of this equation by 2 to get 3x - 80 = y<BR>\n" );
document.write( "that should be your solution because that is the value of y in terms of x.<BR>\n" );
document.write( "the solution is y = 3x - 80.\r<BR>\n" );
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