document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1147440>Question 1147440</A>: <I><SPAN STYLE=\"word-break: break-all;\"> How many ounces of a 13% alcohol solution must be mixed with 3 ounces of a 20% alcohol solution to make a 16% alcohol solution?<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #768801 by </B><A HREF=/tutors/aboutme.mpl?userid=greenestamps><B>greenestamps(13200)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=greenestamps><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=greenestamps><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=768801\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> <br><BR>\n" );
document.write( "A quick non-algebraic method for solving mixture problems like this....<br><BR>\n" );
document.write( "(1) The target of 16% is 3/7 of the way from 13% to 20%.  (Picture the three percentages on a number line: 13 to 16 is 3; 13 to 20 is 7; 16 is 3/7 of the way from 13 to 20.)<br><BR>\n" );
document.write( "(2) That means 3/7 of the mixture is the higher percentage ingredient.<br><BR>\n" );
document.write( "That 3/7 of the mixture is 3 ounces, so the other 4/7 of the mixture is 4 ounces.<br><BR>\n" );
document.write( "ANSWER: 4 ounces of the 13% solution </SPAN>\n" );
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