document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1147461>Question 1147461</A>: <I><SPAN STYLE=\"word-break: break-all;\"> If 𝑠(𝑡)=(1/2)t^4-5t^3+12t^2, find the velocity of the object when its acceleration is zero.<BR>\n" );
document.write( " </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #768792 by </B><A HREF=/tutors/aboutme.mpl?userid=Alan3354><B>Alan3354(69443)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Alan3354><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Alan3354><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=768792\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> If 𝑠(𝑡)=(1/2)t^4-5t^3+12t^2, find the velocity of the object when its acceleration is zero.<BR>\n" );
document.write( "----------------<BR>\n" );
document.write( "The 1st derivative is speed.<BR>\n" );
document.write( "𝑠(𝑡)=(1/2)t^4-5t^3+12t^2<BR>\n" );
document.write( "𝑠'(𝑡)= 2t^3 - 15t^2 + 24t<BR>\n" );
document.write( "========================<BR>\n" );
document.write( "The 2nd derivative is accel:<BR>\n" );
document.write( "𝑠\"(𝑡)= 6t^2 - 30t + 24<BR>\n" );
document.write( "==================================<BR>\n" );
document.write( "6t^2 - 30t + 24 = 0<BR>\n" );
document.write( "t^2 - 5t + 4 = 0<BR>\n" );
document.write( "t = -1, -4<BR>\n" );
document.write( "********************************<BR>\n" );
document.write( "********************************<BR>\n" );
document.write( "𝑠'(𝑡)= 2t^3 - 15t^2 + 24t<BR>\n" );
document.write( "Sub the values t = -1 and t = -4\r<BR>\n" );
document.write( "<BR>\n" );
document.write( "\n" );
document.write( " </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );