document.write( "Question 1147421: You biked uphill for 3.5 hours. The return trip took 2.5 hours because you traveled 2mph faster. How far did you travel downhill? \n" ); document.write( "

Algebra.Com's Answer #768745 by josmiceli(19441) $\"\"$ $\"About$

You can put this solution on YOUR website!
Let $\"+d+\"$ = the one-way distance
\n" ); document.write( "Let $\"+s+\"$ = speed going uphill in mi/hr
\n" ); document.write( "----------------------------------------------
\n" ); document.write( "Going uphill:
\n" ); document.write( "(1) $\"+d+=+s%2A3.5+\"$
\n" ); document.write( "Going downhill:
\n" ); document.write( "(2) $\"+d+=+%28+s+%2B+2+%29%2A2.5+\"$
\n" ); document.write( "-----------------------------
\n" ); document.write( " $\"+s%2A3.5+=+%28+s+%2B+2+%29%2A2.5+\"$
\n" ); document.write( " $\"+3.5s+-+2.5s+=+5+\"$
\n" ); document.write( " $\"+s+=+5+\"$
\n" ); document.write( "and
\n" ); document.write( "(1) $\"+d+=+5%2A3.5+\"$
\n" ); document.write( "(1) $\"+d+=+17.5+\"$ mi
\n" ); document.write( "-------------------------
\n" ); document.write( "I traveled 17.5 mi downhill
\n" ); document.write( "-------------------------------
\n" ); document.write( "check:
\n" ); document.write( "(2) $\"+d+=+%28+s+%2B+2+%29%2A2.5+\"$
\n" ); document.write( "(2) $\"+17.5+=+2.5s+%2B+5+\"$
\n" ); document.write( "(2) $\"+2.5s+=+12.5+\"$
\n" ); document.write( "(2) $\"+s+=+5+\"$
\n" ); document.write( "OK \n" ); document.write( "

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