document.write( "Question 1147317: sam flew a distance of 500 miles at a normal speed. on the trip back (also 500 miles) sam doubled the speed of the plane. how fast did sam fly on the trip back if the total travelling time was 5 hours? \n" ); document.write( "

Algebra.Com's Answer #768658 by ikleyn(52803) $\"\"$ $\"About$

You can put this solution on YOUR website!
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document.write( "Let \"x\" be the speed flying 500 miles \"to there\", in miles per hour.\r\n" );
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document.write( "Then the speed flying back was  2x  miles per hour.\r\n" );
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document.write( "Then the \"time\" equation is\r\n" );
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document.write( "     +  = 5  hours\r\n" );
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document.write( "saying that the total time flying \"to there\" and back was 5 hours.\r\n" );
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document.write( "To solve the \"time\" equation, multiply both sides by 2x.  You will get\r\n" );
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document.write( "    1000 + 500 = 10x\r\n" );
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document.write( "    1500       = 10x\r\n" );
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document.write( "      x        =  = 150 miles per hour.\r\n" );
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document.write( "Thus the average speed flying \"to there\" was 150 mph;  hence, the average speed flying back was twice of it, i.e. 300 mph.    ANSWER\r\n" );
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