document.write( "Question 1147309: Twice Kent's age now is the same as three times his age two years ago. How old is he now? \n" ); document.write( "
Algebra.Com's Answer #768630 by ankor@dixie-net.com(22740)![]() ![]() You can put this solution on YOUR website! Twice Kent's age now is the same as three times his age two years ago. \n" ); document.write( "2k = 3(k-2) \n" ); document.write( "2k = 3k - 6 \n" ); document.write( "2k - 3k = -6 \n" ); document.write( "-k = -6 \n" ); document.write( "k = 6 \n" ); document.write( " How old is he now? 6 yrs old now \n" ); document.write( ": \n" ); document.write( "Check: \"Twice Kent's age now is the same as three times his age two years ago. \" \n" ); document.write( "2(6) = 3(6 - 2) \n" ); document.write( "12 = 3(4) \n" ); document.write( " |