document.write( "Question 1147284: The length of a new rectangular playing field is 2 yards longer than quadruple the width. If the perimeter of the rectangular playing field is 454 yards, what are its dimensions? \n" ); document.write( "

Algebra.Com's Answer #768595 by rothauserc(4718) $\"\"$ $\"About$

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let l be the length of the rectangular playing field and w be its width, then
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\n" ); document.write( "l = 4w +2
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\n" ); document.write( "Perimeter = 2l +2w
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\n" ); document.write( "2(4w +2) + 2w = 454
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\n" ); document.write( "8w +4 +2w = 454
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\n" ); document.write( "10w = 450
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\n" ); document.write( "w = 45
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\n" ); document.write( "l = 4(45) +2 = 182
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\n" ); document.write( "The dimensions of the rectangular playing field are length 182 yards and width is 45 yards
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\n" ); document.write( "check the answer
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\n" ); document.write( "2(182) +2(45) = 454
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\n" ); document.write( "364 + 90 = 454
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\n" ); document.write( "454 = 454
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