document.write( "Question 1147211: Sherlock made an elaborate code to remember the 10-digit combination to his locker. This is the code he came up with:\r
\n" ); document.write( "\n" ); document.write( "A - K - B - J - C - H - D - G - E - F\r
\n" ); document.write( "\n" ); document.write( "Each letter stands for a different single digit number, from 0-9.\r
\n" ); document.write( "\n" ); document.write( "To find the combination, study the clues below to figure out what digit is represented by each letter. When two letters are written together without an operation symbol, they represent a tens digit and a ones digit.\r
\n" ); document.write( "\n" ); document.write( "D + D + D = F
\n" ); document.write( "H + H = B
\n" ); document.write( "G + B +E = F + A +C
\n" ); document.write( "J + A = CC
\n" ); document.write( "F x D = KG (x means multiplied by)
\n" ); document.write( "B / H = K (/ means divided by)
\n" ); document.write( "D x H = CK
\n" ); document.write( "A x H = KE
\n" ); document.write( "J / D = K
\n" ); document.write( "D H (this is fractions, D over J and H over B)
\n" ); document.write( "- = -
\n" ); document.write( "J B\r
\n" ); document.write( "\n" ); document.write( "What is the 10 digit combination to Sherlock's locker?
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Algebra.Com's Answer #768565 by MathLover1(20850)\"\" \"About 
You can put this solution on YOUR website!

\n" ); document.write( "\"H+%2B+H+=+2H+=+B\", so \"H%2FB+=+1%2F2\" \r
\n" ); document.write( "\n" ); document.write( "Then \"D%2FJ+=+1%2F2\", so \"J%2FD+=+2\"
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\n" ); document.write( "Hence \"K+=+2\". \r
\n" ); document.write( "\n" ); document.write( "We therefore also have a bunch of doubling pairs: 1-2, 2-4, 3-6, 4-8. But \"K=2\", so \"J\" and \"D\" are either 3-6 or 4-8. \r
\n" ); document.write( "\n" ); document.write( "Note that \"J\" & \"D\" are one set, and \"H\" & \"B\" are the other distinct set. \r
\n" ); document.write( "\n" ); document.write( "Further, \"D\" and \"F\" are a \"tripled\" pair. \r
\n" ); document.write( "\n" ); document.write( "Note that \"F+=+3D\", so\"+D\" = 1,2,3. But from above, \"D\"=3,4, so \"D+=+3\". \r
\n" ); document.write( "\n" ); document.write( "Then \"J+=+6\" and \"F+=+9\". Further, \"HB\" must be the other double pair available, 4-8. Hence \"H+=+4\" and \"B+=+8\". \r
\n" ); document.write( "\n" ); document.write( "Now, \"F+%2A+D+=+9+%2A+3+=+27+=+KG\", so \"G+=+7\". \r
\n" ); document.write( "\n" ); document.write( "Since \"J+=+6\" and \"J+%2B+A+=+CC\", \"J%2BA+%3C+16\" so \"CC+=+11\" and \"C+=+1\". \r
\n" ); document.write( "\n" ); document.write( "Further, \"A+=+5\". Then \"A%2A+H+=+KE\" => \"5+%2A+4+=+2E+=+20\", so \"E+=+0\".\r
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\n" ); document.write( "\n" ); document.write( "solution: \"A+-+K+-+B+-+J+-+C+-+H+-+D+-+G+-+E+-+F\" is \"5-2-8-6-1-4-3-7-0-9\"\r
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