document.write( "Question 1146973: if x = (a + (a²+b³)^1/2)^1/3 + (a - (a²+b³)^1/2)^1/3) then x³ + 3bx ise \n" ); document.write( "
Algebra.Com's Answer #768563 by ikleyn(52908)\"\" \"About 
You can put this solution on YOUR website!
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\n" ); document.write( "\n" ); document.write( "            Looking into the solution by Edwin,  not every school student knows about the formula  Cardano.\r
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\n" ); document.write( "\n" ); document.write( "            So, I think,  more simple and more accessible solution is expected and is required.\r
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\n" ); document.write( "\n" ); document.write( "            See such a solution below.  It uses nothing that goes outside of the standard school Math curriculum.\r
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\n" ); document.write( "\n" ); document.write( "            Nothing --- except combining standard knowledge in the right order :)\r
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document.write( "I will introduce new variables  u = \"%28a%2B%28a%5E2%2Bb%5E3%29%5E%281%2F2%29%29%5E%281%2F3%29\"  and  v = \"%28a-%28a%5E2%2Bb%5E3%29%5E%281%2F2%29%29%5E%281%2F3%29\".\r\n" );
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document.write( "Then  \r\n" );
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document.write( "    \"u%5E3\" = \"a%2B%28a%5E2%2Bb%5E3%29%5E%281%2F2%29\",\r\n" );
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document.write( "    \"v%5E3\" = \"a-%28a%5E2%2Bb%5E3%29%5E%281%2F2%29\",    \r\n" );
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document.write( "    x = u + v,\r\n" );
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document.write( "    \"u%5E3%2Av%5E3\" = \"%28a%2B%28a%5E2%2Bb%5E3%29%5E%281%2F2%29%29\".\"%28a-%28a%5E2%2Bb%5E3%29%5E%281%2F2%29%29\" = \"%28a%2Bsqrt%28a%5E2%2Bb%5E3%29%29%2A%28a-sqrt%28a%5E2%2Bb%5E3%29%29\" = \"%28a%5E2+-+%28a%5E2+%2B+b%5E3%29%29\" = \"-b%5E3\";\r\n" );
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document.write( "           therefore,  \"u%2Av\" = \"%28-b%5E3%29%5E%281%2F3%29\" = -b.\r\n" );
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document.write( "    Thus we have  x = u + v,   \"u%5E3\" + \"v%5E3\" = 2a,  and  u*v = -b.    (1)\r\n" );
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document.write( "Next,  \"x%5E3\" = \"%28u%2Bv%29%5E3\" = \"u%5E3\" + \"3u%5E2%2Av\" + \"3u%2Av%5E2\" + \"v%5E3\" = \"u%5E3%2Bv%5E3\" + \"3uv%2A%28u%2Bv%29\".\r\n" );
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document.write( "Substitute here from (1), and you will get\r\n" );
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document.write( "    \"x%5E3\" = 2a + 3*(-b)*x = 2a - 3bx.\r\n" );
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document.write( "Therefore,\r\n" );
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document.write( "    \"x%5E3\" + 3bx = 2a.         ANSWER\r\n" );
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\n" ); document.write( "\n" ); document.write( "Completed and solved,  and an  ELEMENTARY  solution is obtained.\r
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