document.write( "Question 1147218: Determine the amount of money that will be accumulated in an account that pays compound interest, given the initial principal of $27,800 invested at 2.97% annual interest for 9 years compounded
\n" );
document.write( "(a) daily (n=365);
\n" );
document.write( "(b) continuously. \n" );
document.write( "
Algebra.Com's Answer #768543 by Theo(13342) You can put this solution on YOUR website! discrete compounding formula is f = p * (1 + r) ^ n \n" ); document.write( "f is the future value \n" ); document.write( "p is the present value \n" ); document.write( "r is the interest rate per time period \n" ); document.write( "n is the number of time periods\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "continuous compounding formula is f = p * e ^ (r * t) \n" ); document.write( "f is the future value \n" ); document.write( "p is the present value \n" ); document.write( "r is the interest rate per time period \n" ); document.write( "n is the number of time periods\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "using the discrete compounding formula, your problem becomes:\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "f = 27500 * (1 + .0297/365) ^ (9 * 365) = 35,926.49804.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "using the continuous compounding formula, your problem becomes;\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "f = 27500 * e ^ (.0297 * 9) = 35,926.88872.\r \n" ); document.write( "\n" ); document.write( "we could also have done:\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "f = 27500 * e ^ (.0297/365 * 9 * 365) = 35,926.88872.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "since the compounding is continuous, it doesn't matter what time periods we use as long as we're consistant, i.e. r = annual interest rate / number of compounding periods per year paired with n = number of years * number of compounding periods per year.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "also note that daily compounding gets pretty close to continuous compounding. \n" ); document.write( "the more compounding periods per year you get, the closer you get to continuous compounding results.\r \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |