document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1147128>Question 1147128</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Distribution with a mean of 123 and standard deviation of 8 is transformed into a standardized distribution with a mean of 54 and standard deviation of 5. Find the new standardized score when the original value is X=130\r<BR>\n" );
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document.write( "My solution:<BR>\n" );
document.write( "130-123/8 = 0.875\r<BR>\n" );
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document.write( "In the standardized distribution: 5*0.875=4.375<BR>\n" );
document.write( "So new score is 54 + 4.375= 58. 375 ? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #768484 by </B><A HREF=/tutors/aboutme.mpl?userid=Boreal><B>Boreal(15235)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Boreal><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Boreal><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=768484\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Yes, that's how you do it.<BR>\n" );
document.write( "The z score for the value of 130 in the original distribution is 7/8<BR>\n" );
document.write( "Therefore, that has to be the z-score of the new value in the second distribution.<BR>\n" );
document.write( "Since the z-score is (x-mean)/sd you get the result you got.<BR>\n" );
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