document.write( "Question 1147164: The freshness of a product at a superstore is rated on a scale of 1 to 5 with 5 being very fresh. From a random sample of 49 customers, the average score was 3.8. The standard deviation of this population is 0.7.\r
\n" ); document.write( "\n" ); document.write( "1. Obtain a 95% confidence interval for the population mean, μ, the mean score for the distribution of all possible customers. \r
\n" ); document.write( "\n" ); document.write( "2. Does μ lie in your interval obtained in part (i)? Explain.
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Algebra.Com's Answer #768479 by Boreal(15235)\"\" \"About 
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interval is +/- z*sigma/sqrt (n) and for 95% CI, half-interval is 1.96*0.7/sqrt(49)
\n" ); document.write( "This is 0.196
\n" ); document.write( "the 95% CI is mu+/-0.196 or (3.60, 3.80)
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