document.write( "Question 1147131: Jack is one year older than twice Ben’s age. Frank is three years younger than Jack. Write an expression for Frank’s H in relation to Ben’s age \n" ); document.write( "
Algebra.Com's Answer #768429 by ikleyn(52786)![]() ![]() You can put this solution on YOUR website! . \n" ); document.write( " \r\n" ); document.write( "\r\n" ); document.write( "Start from\r\n" ); document.write( "\r\n" ); document.write( "\r\n" ); document.write( " F = J - 3 (1) (\"Frank is three years younger than Jack\")\r\n" ); document.write( "\r\n" ); document.write( "\r\n" ); document.write( "From the other side, you are given\r\n" ); document.write( "\r\n" ); document.write( "\r\n" ); document.write( " J = 2B + 1 (2) (\"Jack is one year older than twice Ben’s age\")\r\n" ); document.write( "\r\n" ); document.write( "\r\n" ); document.write( "Substitute (2) into (1). You will jet\r\n" ); document.write( "\r\n" ); document.write( "\r\n" ); document.write( " F = (2B + 1) - 3,\r\n" ); document.write( "\r\n" ); document.write( "\r\n" ); document.write( "which is\r\n" ); document.write( "\r\n" ); document.write( "\r\n" ); document.write( " F = 2B - 2. ANSWER\r\n" ); document.write( "\r \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |