document.write( "Question 105559: i have to graph this equation. 6X-3Y=9, so far i think i add 2 n 9 together n then divide my answer by 2 is that correct? \n" ); document.write( "
Algebra.Com's Answer #76838 by ankor@dixie-net.com(22740)\"\" \"About 
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i have to graph this equation. 6X-3Y = 9,
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\n" ); document.write( "Quite frankly, I have no idea what you are doing, but to graph this:
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\n" ); document.write( "Put in the general \"y=\"
\n" ); document.write( "6x - 3y = 9
\n" ); document.write( "-3y = -6x + 9
\n" ); document.write( "We want y to be positive, multiply eq by =-1
\n" ); document.write( "+3y = +6x - 9
\n" ); document.write( "Divide equation by 3 and you have:
\n" ); document.write( "y = 2x - 3
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\n" ); document.write( "With this equation, substitute values for x and find y, make a table from these values.
\n" ); document.write( "You only need two since it is a straight line but here are 3:
\n" ); document.write( "If x = -3
\n" ); document.write( "y = 2(-3) - 3
\n" ); document.write( "y = -6 - 3
\n" ); document.write( "y = -9
\n" ); document.write( ":
\n" ); document.write( "If x = 0:
\n" ); document.write( "y = 2(0) -3
\n" ); document.write( "y = -3
\n" ); document.write( ":
\n" ); document.write( "If x = +3
\n" ); document.write( "y = 2(3) - 3
\n" ); document.write( "y = 6 - 3
\n" ); document.write( "y = +3
\n" ); document.write( ":
\n" ); document.write( "The table:
\n" ); document.write( " x | y
\n" ); document.write( "--------
\n" ); document.write( "-3 |-9
\n" ); document.write( " 0 |-3
\n" ); document.write( "+3 |+3\r
\n" ); document.write( "\n" ); document.write( ":
\n" ); document.write( "If you plot this, it should look like this:
\n" ); document.write( "\"+graph%28+300%2C+200%2C+-10%2C+10%2C+-10%2C+10%2C+2x-3%29+\"
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\n" ); document.write( "Did this shed any light on this graphing stuff for you? \n" ); document.write( "
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