document.write( "Question 1147059: Hi, I have a question concerning me before a test. The problem is that Jake needs to buy 120 beverages. X is packs of 8 for juice and y is packs of 12 for water. We have to write it in standard form and so far I have tried 8x + 12y = 120 and that would mean that y = 10 and x = 15. I was just wondering if that is correct. Thanks \n" ); document.write( "
Algebra.Com's Answer #768361 by MathTherapy(10552)\"\" \"About 
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Hi, I have a question concerning me before a test. The problem is that Jake needs to buy 120 beverages. X is packs of 8 for juice and y is packs of 12 for water. We have to write it in standard form and so far I have tried 8x + 12y = 120 and that would mean that y = 10 and x = 15. I was just wondering if that is correct. Thanks
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Your answers are NOT correct, but your equation is, but you need to be consistent, as \"x+%3C%3E+X\"
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document.write( "I'll use the lower case variable. This will give: 
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document.write( "You should realize that the number of packs of juice, as well as the number of packs of water MUST have integer values.
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document.write( "If you look at the equation: \"matrix%281%2C3%2C+x%2C+%22=%22%2C+%2830+-+3y%29%2F2%29\", it's obvious that y, or the number of packs of water, can be 10. If you substitute that value for y, you'll get an INTEGER value for the number of packs of juice. 
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document.write( "Now, since we need to decrease the number of packs of water (increasing this number will lead to a NEGATIVE number of packs of juice), the next integer value, down from 10 is 9. 
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document.write( "If 9 is used, you'll get a NON-INTEGER value for the packs of juice. So, 9 DOESN'T work. If you continue, you'll notice that ONLY EVEN VALUES of packs of water, from 10, down to 0, will work. 
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document.write( "Therefore, your answer will be varying packs of juice, depending on the varying EVEN-NUMBER of packs of water, from 10, down to 0, or from 0 to 10. 
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document.write( "If you're confused, this is what you should get:  \n" );
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