document.write( "Question 1147027: Hi
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document.write( "A B and C had 181 cookies at first. A gave away 20% of her cookies while B bought 28 more cookies. C also bought more cookies and had 4 times as many as before. Then the ratio of the number of cookies A B C had was 2:5:8 respectively. How many cookies did B have at first.\r
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document.write( "thanks \n" );
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Algebra.Com's Answer #768317 by ikleyn(52798)![]() ![]() You can put this solution on YOUR website! . \n" ); document.write( " \r\n" ); document.write( "Let \"a\", \"b\" and \"c\" be the numbers of cookies that A, B and C had originally.\r\n" ); document.write( "\r\n" ); document.write( "\r\n" ); document.write( "The first equation is\r\n" ); document.write( "\r\n" ); document.write( "\r\n" ); document.write( " a + b + c = 181. (1)\r\n" ); document.write( "\r\n" ); document.write( "\r\n" ); document.write( "After all events, A had 0.8a cookies, B had (b+28) and C had 4c cookies.\r\n" ); document.write( "\r\n" ); document.write( "\r\n" ); document.write( "We are given this long proportion 0.8a : (b+28) : 4c = 2 : 5 : 8.\r\n" ); document.write( "\r\n" ); document.write( "\r\n" ); document.write( "It means that\r\n" ); document.write( "\r\n" ); document.write( " 0.8a = 2x,\r\n" ); document.write( "\r\n" ); document.write( " b+28 = 5x\r\n" ); document.write( "\r\n" ); document.write( " 4c = 8x\r\n" ); document.write( "\r\n" ); document.write( "for some unknown number x.\r\n" ); document.write( "\r\n" ); document.write( "\r\n" ); document.write( "From these equations, \r\n" ); document.write( "\r\n" ); document.write( "\r\n" ); document.write( " a =\r \n" ); document.write( "\n" ); document.write( "Just instructed / and completed.\r \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |