document.write( "Question 1147027: Hi
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document.write( "A B and C had 181 cookies at first. A gave away 20% of her cookies while B bought 28 more cookies. C also bought more cookies and had 4 times as many as before. Then the ratio of the number of cookies A B C had was 2:5:8 respectively. How many cookies did B have at first.\r
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document.write( "thanks \n" );
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Algebra.Com's Answer #768316 by greenestamps(13200)![]() ![]() You can put this solution on YOUR website! \n" ); document.write( "Let the numbers for each person be A, B, and C. Then the given information tells us \n" ); document.write( "(1) A+B+C = 181 \n" ); document.write( "(2) (4/5)A : B+28 : 4C = 2:5:8 \n" ); document.write( "Use the ratios in (2) to get B and C in terms of A and substitute in (1). \n" ); document.write( "(Of course you could also get A and C in terms of B, or A and B in terms of C....) \n" ); document.write( "B in terms of A: \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "C in terms of A: \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "Substitute and solve for A: \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "Use this value of A to find B and C: \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "Original numbers of cookies: \n" ); document.write( "A = 55 \n" ); document.write( "B = 82 \n" ); document.write( "C = 44 \n" ); document.write( " |