document.write( "Question 1147010: A company manufactures two types of​ washers, top load and front load. The company can manufacture a maximum of 18 washers per day. It makes a profit of​ $20 on top load machines and​ $25 on front load machines. No more than 5 front load machines can be manufactured due to production restrictions. To meet consumer​ demand, the company must manufacture at least 2 front load machines and 2 top load machines per day. What is the maximum​ profit? \n" ); document.write( "
Algebra.Com's Answer #768302 by Theo(13342)\"\" \"About 
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x = number of top loaders.
\n" ); document.write( "y = number of front loaders.
\n" ); document.write( "constraint equations are:
\n" ); document.write( "x + y <= 18
\n" ); document.write( "y <= 5
\n" ); document.write( "x >= 2
\n" ); document.write( "y >= 2
\n" ); document.write( "objective function is:
\n" ); document.write( "profit = 20x + 25y\r
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\n" ); document.write( "\n" ); document.write( "using the desmos.com calculator, graph the opposite of these inequalities.
\n" ); document.write( "the area on the graph that is not shaded is your region of feasibility.
\n" ); document.write( "the corner points of this region are where the maximum profit will lie.\r
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\n" ); document.write( "\n" ); document.write( "here's the graph.\r
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\n" ); document.write( "\n" ); document.write( "the highest pofit is when x = 13 and y = 5.
\n" ); document.write( "that's the point (13,5) on the graph.
\n" ); document.write( "the profit is 13 * 20 + 5 * 25 = 385
\n" ); document.write( "all the constraint are met, as shown below.
\n" ); document.write( "x + y <= 18
\n" ); document.write( "y <= 5
\n" ); document.write( "x >= 2
\n" ); document.write( "y >= 2\r
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\n" ); document.write( "\n" ); document.write( "solution is that maximum profit is 385 dollars.\r
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