document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=105570>Question 105570</A>This question is from textbook <A HREF=http://www.amazon.com/exec/obidos/ASIN/0534493947/algebrahomeworkh>Intermediate Algebra</A><BR>\n" );
document.write( ": <I><SPAN STYLE=\"word-break: break-all;\"> I need someone's help. I need to find the value of x from logx169/121= 2??<BR>\n" );
document.write( "Can someone please help me out on this?? Thank You! </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #76830 by </B><A HREF=/tutors/aboutme.mpl?userid=bucky><B>bucky(2189)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=bucky><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=76830\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> You are given the equation:<BR>\n" );
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document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=log%28x%2C%28169%2F121%29%29=+2 ALIGN=MIDDLE  ALT=\"log%28x%2C%28169%2F121%29%29=+2\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
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document.write( "To solve for x you can convert the given logarithmic equation to its equivalent exponential<BR>\n" );
document.write( "form using the following translation format:<BR>\n" );
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document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=log%28b%2CA%29=+y ALIGN=MIDDLE  ALT=\"log%28b%2CA%29=+y\"   DISABLED_style= \"max-width:90%; height:auto;\" > is equivalent to the exponential form <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=b%5Ey+=+A ALIGN=MIDDLE  ALT=\"b%5Ey+=+A\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
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document.write( "Note that by comparing the given equation to the translation format you can see from the<BR>\n" );
document.write( "positions in the equations that:<BR>\n" );
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document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=b+=+x ALIGN=MIDDLE  ALT=\"b+=+x\"   DISABLED_style= \"max-width:90%; height:auto;\" >, <BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=A+=+169%2F121 ALIGN=MIDDLE  ALT=\"A+=+169%2F121\"   DISABLED_style= \"max-width:90%; height:auto;\" > and <BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=y+=+2 ALIGN=MIDDLE  ALT=\"y+=+2\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
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document.write( "Substituting values for b, A, and y into the exponential form results in:<BR>\n" );
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document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=x%5E2+=+169%2F121 ALIGN=MIDDLE  ALT=\"x%5E2+=+169%2F121\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
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document.write( "You can then solve for x by taking the square root of both sides to get:<BR>\n" );
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document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=x+=+sqrt%28169%2F121%29+=+%28sqrt%28169%29%29%2F%28sqrt%28121%29%29+=+13%2F11 ALIGN=MIDDLE  ALT=\"x+=+sqrt%28169%2F121%29+=+%28sqrt%28169%29%29%2F%28sqrt%28121%29%29+=+13%2F11\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
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document.write( "So the answer to your problem is <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=x+=+13%2F11 ALIGN=MIDDLE  ALT=\"x+=+13%2F11\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
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document.write( "It's a good idea to become very familiar with switching back and forth between the logarithmic <BR>\n" );
document.write( "and exponential forms. This switching is often used in solving logarithmic equations.<BR>\n" );
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document.write( "Hope this helps you to understand this problem.<BR>\n" );
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