document.write( "Question 1146948: Give an example of a rational function h whose graph has the following properties.\r
\n" ); document.write( "\n" ); document.write( "vertical asymptote: x = -1 and x = 2
\n" ); document.write( "horizontal asymptote: y = 3\r
\n" ); document.write( "\n" ); document.write( "x-intercept: (3, 0)
\n" ); document.write( "

Algebra.Com's Answer #768250 by greenestamps(13200)\"\" \"About 
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\n" ); document.write( "(1) vertical asymptote: x = -1 and x = 2

\n" ); document.write( "This means there are factors of (x+1) and (x-2) in the denominator:

\n" ); document.write( "\"a%2F%28%28x%2B1%29%28x-2%29%29\"

\n" ); document.write( "(2) x-intercept: (3, 0)

\n" ); document.write( "This means there is a factor of (x-3) in the numerator:

\n" ); document.write( "\"%28a%28x-3%29%29%2F%28%28x%2B1%29%28x-2%29%29\"

\n" ); document.write( "(3) horizontal asymptote: y = 3

\n" ); document.write( "This means there is a constant factor of 3 in the numerator; and the degrees of the numerator and denominator are the same. So, in addition to the constant factor 3, we need a second linear factor in the numerator. It can be any linear factor; I chose x, meaning there is a second x-intercept at x=0:

\n" ); document.write( "\"%283%28x%29%28x-3%29%29%2F%28%28x%2B1%29%28x-2%29%29\"

\n" ); document.write( "Here is a graph:

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\n" ); document.write( "If the statement of the problem is supposed to imply that x=3 is the ONLY x-intercept, then we can make the second linear factor in the numerator (x-3) also. Note that means the graph will be tangent to the x-axis at x=3:

\n" ); document.write( "\"%283%28x-3%29%5E2%29%2F%28x%2B1%29%28x-2%29%29\"

\n" ); document.write( "Here is a graph:

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