document.write( "Question 1146954: In a two-digit number, 5 times the units digit added to the tens digit equals 43. Five times the tens digit added to the units digit equals 47. Find the number
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Algebra.Com's Answer #768231 by Theo(13342)\"\" \"About 
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let x = the value of the tens digit.
\n" ); document.write( "let y = the value of the ones digit.
\n" ); document.write( "the number is 10x + y.
\n" ); document.write( "example: in the number 57, 5 is the value of the tens digit and 7 is the value of the ones digit and the number is 10 * 5 + 7 = 57.
\n" ); document.write( "this is because each tens digit is worth 10 units while each units digit is worth 1 unit.
\n" ); document.write( "your equations are:
\n" ); document.write( "x + 5y = 43
\n" ); document.write( "5x + y = 47
\n" ); document.write( "multiply both sides of the first equation by 5 and leave the second equation as is to get:
\n" ); document.write( "5x + 25y = 215
\n" ); document.write( "5x + y = 47
\n" ); document.write( "subtract the second equation from the first to get:
\n" ); document.write( "24y = 168
\n" ); document.write( "solve for y to get:
\n" ); document.write( "y = 7
\n" ); document.write( "replace y with 7 in the second equation of 5x + y = 47 to get:
\n" ); document.write( "5x + 7 = 47
\n" ); document.write( "subtract 7 from both sides to get:
\n" ); document.write( "5x = 40
\n" ); document.write( "solve for x to get:
\n" ); document.write( "x = 8
\n" ); document.write( "replace x with 8 and y with 7 in both original equqations to get:
\n" ); document.write( "x + 5y = 43 becomes 8 + 35 = 43 which becomes 43 = 43 which is true.
\n" ); document.write( "5x + y = 47 becomes 40 + 7 = 47 which becomes 47 = 47 which is true.
\n" ); document.write( "both original equation are true when x = 8 and y = 7.
\n" ); document.write( "your number is 10x + y which is equal to 87.
\n" ); document.write( "that's your solution.
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