document.write( "Question 1146889: graph : |x^2-1|
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Algebra.Com's Answer #768175 by ikleyn(52797)\"\" \"About 
You can put this solution on YOUR website!
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document.write( "Step 1:  graph  \"x%5E2+-+1\",  without the modulus sign.\r\n" );
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document.write( "         It is simple parabola,  see below\r\n" );
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document.write( "    \"graph%28+330%2C+330%2C+-5%2C+5%2C+-5%2C+10%2C%0D%0A+++++++++++++++x%5E2-1%0D%0A%29\"\r\n" );
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document.write( "    Plot  y = \"x%5E2+-+1\".\r\n" );
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document.write( "Step 2.  \r\n" );
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document.write( "    Do you see this part of the parabola between  x= -1  and  x= 1, which is BELOW x-axis ?\r\n" );
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document.write( "    Reflect it about the x-axis, as if this part of the x-axis  -1 <= x <= 1  is a mirror.\r\n" );
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document.write( "    You will get the plot of your ORIGINAL function  y = \"abs%28x%5E2-1%29\".\r\n" );
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document.write( "    \"graph%28+330%2C+330%2C+-5%2C+5%2C+-5%2C+10%2C%0D%0A+++++++++++++++abs%28x%5E2-1%29%0D%0A%29\"\r\n" );
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document.write( "    Plot  y = \"abs%28x%5E2+-+1%29\".\r\n" );
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document.write( "Step 3.  Do not forget to post your \"THANKS\" to me for my lesson.\r\n" );
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