document.write( "Question 1146813: 2x + y - 2z = -1
\n" ); document.write( "3x - 3y - z = 5
\n" ); document.write( "x - 2y + 3z = 6
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Algebra.Com's Answer #768117 by josgarithmetic(39618)\"\" \"About 
You can put this solution on YOUR website!
This was done without rechecking:\r
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document.write( "2  1  -1  -1\r\n" );
document.write( "3  -3  -1 5\r\n" );
document.write( "1 -2  3   6\r\n" );
document.write( "\r\n" );
document.write( "0  5  -8  -13\r\n" );
document.write( "0  3  -10 -13\r\n" );
document.write( "1 -2  3   6\r\n" );
document.write( "then switch rows\r\n" );
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document.write( "1  -2  3  6\r\n" );
document.write( "0  5  -8 -13\r\n" );
document.write( "0  3  -10 -13\r\n" );
document.write( "\r\n" );
document.write( "1  -2  3  6\r\n" );
document.write( "0  15 -24 -29\r\n" );
document.write( "0  15 -50 -65\r\n" );
document.write( "\r\n" );
document.write( "E3-E3-E2;\r\n" );
document.write( "E2+8E3 and  E1-3E3\r\n" );
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document.write( "1 -2 0 3\r\n" );
document.write( "0  5 0 -5\r\n" );
document.write( "0  0 1  1\r\n" );
document.write( "\r\n" );
document.write( "1 -2  0  3\r\n" );
document.write( "0  1  0 -1\r\n" );
document.write( "0 0  1  1\r\n" );
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document.write( "then E1=E1+2E2\r\n" );
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document.write( "1  0  0  1\r\n" );
document.write( "0  1  0 -1\r\n" );
document.write( "0  0  1  1\r\n" );
document.write( "\r\n" );
document.write( "

\n" ); document.write( "\"system%28x=1%2Cy=-1%2Cz=1%29\"
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