document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1146804>Question 1146804</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Bob has 40 cents in his pocket. If bob has no pennies, how many different coin combinations of quarters, dimes and/or nickels could bob have </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #768112 by </B><A HREF=/tutors/aboutme.mpl?userid=greenestamps><B>greenestamps(13200)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=greenestamps><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=greenestamps><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=768112\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> <br><BR>\n" );
document.write( "Clearly he can only have either 1 quarter or none.<br><BR>\n" );
document.write( "(1) If he has a quarter, that is 25 of the 40 cents; 15 cents remain.  He can have either 1 dime or no dimes; nickels will make up the rest.<br><BR>\n" );
document.write( "2 solutions with 1 quarter.<br><BR>\n" );
document.write( "(2) If he has no quarters, then the number of dimes he can have is any number from 0 to 4; again nickels will make up the rest.<br><BR>\n" );
document.write( "5 solutions with no quarters.<br><BR>\n" );
document.write( "Total number of combinations: 2+5 = 7<br><BR>\n" );
document.write( " </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );