document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=105494>Question 105494</A>: <I><SPAN STYLE=\"word-break: break-all;\"> a collection of 50 coins is worth $5.20.  There are 12 more nickels than dimes, and the rest of the coins are quarters.  How many coins of each type are in the collection?    Thank you </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #76801 by </B><A HREF=/tutors/aboutme.mpl?userid=scott8148><B>scott8148(6628)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=scott8148><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=scott8148><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=76801\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> let x=dimes, so x+12=nickels and 50-(2x+12)=quarters ... working in cents avoids problems with decimal points\r<BR>\n" );
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document.write( "10(x)+5(x+12)+25(38-2x)=520 ... 10x+5x+60+950-50x=520 ... -35x=-490 ... x=14\r<BR>\n" );
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document.write( "x+12=26\r<BR>\n" );
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document.write( "50-(2x+12)=10 </SPAN>\n" );
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