document.write( "Question 1146709: Manuel is 43 years old. Delaney is 30 years old. How many years ago was Manuel's age 2 times Delaney's age? \n" ); document.write( "

Algebra.Com's Answer #767993 by ikleyn(52787) $\"\"$ $\"About$

You can put this solution on YOUR website!
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document.write( "    The difference between their ages is 43-30 = 13 years.\r\n" );
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document.write( "    Hence, Manuel was two times Delaney age, when they were 26 (Manuel) and 13 (Delaney years old.\r\n" );
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document.write( "    It happened 30 - 13 = 17 years ago.\r\n" );
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document.write( "    Let x be \"how many years ago\", i.e, the unknown value under the question.\r\n" );
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document.write( "    Then you have this \"age\" equation\r\n" );
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document.write( "        43 - x = 2*(30-x).\r\n" );
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document.write( "    Simplify and solve for x.\r\n" );
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document.write( "        43 - x = 2*30 - 2x\r\n" );
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document.write( "        2x - x = 2*30 - 43\r\n" );
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document.write( "         x     = 60 - 43 = 17,\r\n" );
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document.write( "    and you have the same answer.\r\n" );
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