document.write( "Question 1146702: A community group holds a dance every few months. It costs $5 to get into the dance and usually 300 people attend. According to the surveys, the group has conducted, for every $0.50 increase in the price of admission, 15 fewer people will go to the dance. The revenue for holding a dance is modeled by the function R(x)= (300-15x)(5+0.50x), where the x is the number for $0.50 increases in price Determine the maximum revenue and the admission price that must be charged to earn it. \n" ); document.write( "

Algebra.Com's Answer #767977 by greenestamps(13200) $\"\"$ $\"About$

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\n" ); document.write( " $\"R%28x%29+=++%28300-15x%29%285%2B0.50x%29+=+-7.5x%5E2%2B75x%2B1500\"$

\n" ); document.write( "The maximum value of the quadratic function y = ax^2+bx+c is when $\"x+=+-b%2F%282a%29\"$ . Use that to find the desired value of x.

\n" ); document.write( "Then remember that \"x\" is not the answer to the question; the answers to the two questions are
\n" ); document.write( "(1) the maximum revenue, $\"%28300-15x%29%285%2B0.50x%29\"$ , and
\n" ); document.write( "(2) the admission price that will yield that maximum revenue, $\"5%2B0.5x\"$

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