document.write( "Question 1146675: Two different candles are lit. They burn at different rates and one is 3 cm longer than the other. The longer one was lit at 5:30 pm and the shorter one at 7 pm. At 9:30 pm they were both the same length. The longer one burned out at 11:30 pm and the shorter one burned out at 11 pm. How long was each candle originally? \n" ); document.write( "
Algebra.Com's Answer #767963 by ankor@dixie-net.com(22740)![]() ![]() You can put this solution on YOUR website! Two different candles are lit. \n" ); document.write( " They burn at different rates and one is 3 cm longer than the other. \n" ); document.write( " The longer one was lit at 5:30 pm and the shorter one at 7 pm. \n" ); document.write( " At 9:30 pm they were both the same length. \n" ); document.write( " The longer one burned out at 11:30 pm and the shorter one burned out at 11 pm. \n" ); document.write( " How long was each candle originally? \n" ); document.write( ": \n" ); document.write( "let a = the length of the longer candle \n" ); document.write( "let b = the length of the shorter \n" ); document.write( " : \n" ); document.write( "the longer candle burned from 5:30 to 11:30 or 6 hrs, therefore \n" ); document.write( " \n" ); document.write( "and \n" ); document.write( "the shorter candle burned from 7:00 to 11:00 or 4 hrs, therefore \n" ); document.write( " \n" ); document.write( ": \n" ); document.write( "at 9:30 the longer candle has burned for 4 hrs and the shorter for 2.5 hrs \n" ); document.write( "a - 4* \n" ); document.write( "a - \n" ); document.write( "multiply both sides by 12, get rid of the denominator \n" ); document.write( "12a - 8a = 12b - 7.5b \n" ); document.write( "4a = 4.5b \n" ); document.write( "a is 3 cm longer than b, therefore \n" ); document.write( "replace b with (a-3) \n" ); document.write( "4a = 4.5(a-3) \n" ); document.write( "4a = 4.5a - 13.5 \n" ); document.write( "4a - 4.5a = -13.5 \n" ); document.write( "-.5a = -13.5 \n" ); document.write( "a = -13.5/-.5 \n" ); document.write( "a = 27 cm is the longer candle \n" ); document.write( "and obviously \n" ); document.write( "24 cm is the shorter\r \n" ); document.write( "\n" ); document.write( ": \n" ); document.write( "see of this works out \n" ); document.write( "27/6 = 4.5 cm/hr burn rate of the longer \n" ); document.write( "24/4 = 6 cm/hr is the rate of the shorter \n" ); document.write( ": \n" ); document.write( "27 - 4(4.5) = \n" ); document.write( "27 - 18 = 9 cm remain \n" ); document.write( "and \n" ); document.write( "24 - 2.5(6) = \n" ); document.write( "24 - 15 = 9 cm remain \n" ); document.write( " |