document.write( "Question 1146675: Two different candles are lit. They burn at different rates and one is 3 cm longer than the other. The longer one was lit at 5:30 pm and the shorter one at 7 pm. At 9:30 pm they were both the same length. The longer one burned out at 11:30 pm and the shorter one burned out at 11 pm. How long was each candle originally? \n" ); document.write( "
Algebra.Com's Answer #767963 by ankor@dixie-net.com(22740)\"\" \"About 
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Two different candles are lit.
\n" ); document.write( " They burn at different rates and one is 3 cm longer than the other.
\n" ); document.write( " The longer one was lit at 5:30 pm and the shorter one at 7 pm.
\n" ); document.write( " At 9:30 pm they were both the same length.
\n" ); document.write( " The longer one burned out at 11:30 pm and the shorter one burned out at 11 pm.
\n" ); document.write( " How long was each candle originally?
\n" ); document.write( ":
\n" ); document.write( "let a = the length of the longer candle
\n" ); document.write( "let b = the length of the shorter
\n" ); document.write( " :
\n" ); document.write( "the longer candle burned from 5:30 to 11:30 or 6 hrs, therefore
\n" ); document.write( "\"a%2F6\" cm/hr is the rate of burn of the longer
\n" ); document.write( "and
\n" ); document.write( "the shorter candle burned from 7:00 to 11:00 or 4 hrs, therefore
\n" ); document.write( "\"b%2F4\" cm/hr is the rate of burn for the shorter candle
\n" ); document.write( ":
\n" ); document.write( "at 9:30 the longer candle has burned for 4 hrs and the shorter for 2.5 hrs
\n" ); document.write( "a - 4*\"a%2F6\" = b - 2.5*\"b%2F4\"
\n" ); document.write( "a - \"4a%2F6\" = b - \"2.5b%2F4\"
\n" ); document.write( "multiply both sides by 12, get rid of the denominator
\n" ); document.write( "12a - 8a = 12b - 7.5b
\n" ); document.write( "4a = 4.5b
\n" ); document.write( "a is 3 cm longer than b, therefore
\n" ); document.write( "replace b with (a-3)
\n" ); document.write( "4a = 4.5(a-3)
\n" ); document.write( "4a = 4.5a - 13.5
\n" ); document.write( "4a - 4.5a = -13.5
\n" ); document.write( "-.5a = -13.5
\n" ); document.write( "a = -13.5/-.5
\n" ); document.write( "a = 27 cm is the longer candle
\n" ); document.write( "and obviously
\n" ); document.write( "24 cm is the shorter\r
\n" ); document.write( "\n" ); document.write( ":
\n" ); document.write( "see of this works out
\n" ); document.write( "27/6 = 4.5 cm/hr burn rate of the longer
\n" ); document.write( "24/4 = 6 cm/hr is the rate of the shorter
\n" ); document.write( ":
\n" ); document.write( "27 - 4(4.5) =
\n" ); document.write( "27 - 18 = 9 cm remain
\n" ); document.write( "and
\n" ); document.write( "24 - 2.5(6) =
\n" ); document.write( "24 - 15 = 9 cm remain
\n" ); document.write( "
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