document.write( "Question 105510This question is from textbook GEOMETRY
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\n" ); document.write( "\n" ); document.write( "Write an equation of the line that passes through the given point P and has the given slope m\r
\n" ); document.write( "\n" ); document.write( "19. P(-8,-2),m-2/3 \n" ); document.write( "\n" ); document.write( "please help
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Algebra.Com's Answer #76793 by jim_thompson5910(35256)\"\" \"About 
You can put this solution on YOUR website!
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\n" ); document.write( "\n" ); document.write( "If you want to find the equation of line with a given a slope of \"-2%2F3\" which goes through the point (\"-8\",\"-2\"), you can simply use the point-slope formula to find the equation:\r
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\n" ); document.write( "\n" ); document.write( "---Point-Slope Formula---
\n" ); document.write( "\"y-y%5B1%5D=m%28x-x%5B1%5D%29\" where \"m\" is the slope, and is the given point\r
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\n" ); document.write( "\n" ); document.write( "So lets use the Point-Slope Formula to find the equation of the line\r
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\n" ); document.write( "\n" ); document.write( "\"y--2=%28-2%2F3%29%28x--8%29\" Plug in \"m=-2%2F3\", \"x%5B1%5D=-8\", and \"y%5B1%5D=-2\" (these values are given)\r
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\n" ); document.write( "\n" ); document.write( "\"y%2B2=%28-2%2F3%29%28x--8%29\" Rewrite \"y--2\" as \"y%2B2\"\r
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\n" ); document.write( "\n" ); document.write( "\"y%2B2=%28-2%2F3%29%28x%2B8%29\" Rewrite \"x--8\" as \"x%2B8\"\r
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\n" ); document.write( "\n" ); document.write( "\"y%2B2=%28-2%2F3%29x%2B%28-2%2F3%29%288%29\" Distribute \"-2%2F3\"\r
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\n" ); document.write( "\n" ); document.write( "\"y%2B2=%28-2%2F3%29x-16%2F3\" Multiply \"-2%2F3\" and \"8\" to get \"-16%2F3\"\r
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\n" ); document.write( "\n" ); document.write( "\"y=%28-2%2F3%29x-16%2F3-2\" Subtract 2 from both sides to isolate y\r
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\n" ); document.write( "\n" ); document.write( "\"y=%28-2%2F3%29x-22%2F3\" Combine like terms \"-16%2F3\" and \"-2\" to get \"-22%2F3\" (note: if you need help with combining fractions, check out this solver)\r
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\n" ); document.write( "\n" ); document.write( "Answer:\r
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\n" ); document.write( "\n" ); document.write( "So the equation of the line with a slope of \"-2%2F3\" which goes through the point (\"-8\",\"-2\") is:\r
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\n" ); document.write( "\n" ); document.write( "\"y=%28-2%2F3%29x-22%2F3\" which is now in \"y=mx%2Bb\" form where the slope is \"m=-2%2F3\" and the y-intercept is \"b=-22%2F3\"\r
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\n" ); document.write( "\n" ); document.write( "Notice if we graph the equation \"y=%28-2%2F3%29x-22%2F3\" and plot the point (\"-8\",\"-2\"), we get (note: if you need help with graphing, check out this solver)\r
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\n" ); document.write( "\n" ); document.write( " Graph of \"y=%28-2%2F3%29x-22%2F3\" through the point (\"-8\",\"-2\")\r
\n" ); document.write( "\n" ); document.write( "and we can see that the point lies on the line. Since we know the equation has a slope of \"-2%2F3\" and goes through the point (\"-8\",\"-2\"), this verifies our answer.
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