document.write( "Question 1146636: the sum of two numbers is 84.if the difference between half of the first number and one third of the second number is 2,find the two numbers \n" ); document.write( "
Algebra.Com's Answer #767918 by VFBundy(438)\"\" \"About 
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First number = x
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\n" ); document.write( "x + y = 84
\n" ); document.write( "x/2 - y/3 = 2
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\n" ); document.write( "Multiply the second equation by 3:
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\n" ); document.write( "3(x/2 - y/3) = 3(2)
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\n" ); document.write( "3x/2 - y = 6
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\n" ); document.write( "Now, here are your two equations:
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\n" ); document.write( "x + y = 84
\n" ); document.write( "3x/2 - y = 6
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\n" ); document.write( "Add the two equations together:
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\n" ); document.write( "5x/2 = 90
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\n" ); document.write( "Solve for x:
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\n" ); document.write( "5x/2 = 90
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\n" ); document.write( "5x = 180
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\n" ); document.write( "x = 36
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\n" ); document.write( "Now that we know x = 36, we can plug this into any of the previous equations to find y. Use x + y = 84:
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\n" ); document.write( "x + y = 84
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\n" ); document.write( "36 + y = 84
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\n" ); document.write( "y = 48
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\n" ); document.write( "First number = x = 36
\n" ); document.write( "Second number = y = 48 \n" ); document.write( "
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