document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1146602>Question 1146602</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A rhombus has a side length equal to one of the diagonals.The other diagonal is 4c .Find the area of the rhombus. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #767906 by </B><A HREF=/tutors/aboutme.mpl?userid=greenestamps><B>greenestamps(13200)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=greenestamps><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=greenestamps><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=767906\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> <br><BR>\n" );
document.write( "If one of the diagonals is equal to the side length, then that diagonal divides the rhombus into two equilateral triangles.<br><BR>\n" );
document.write( "The other diagonal of the rhombus is composed of the heights of the two equilateral triangles.  Each of those heights has a length equal to sqrt(3)/2 times the side length; so the length of the other diagonal is sqrt(3) times the side length.<br><BR>\n" );
document.write( "Then the area of a rhombus is half the product of the lengths of the diagonals.<br><BR>\n" );
document.write( "You can put those pieces together, along with the given length of the longer diagonal, to finish the problem. </SPAN>\n" );
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