document.write( "Question 1146620: The length of a rectangle is 6 inches less than 3 times the width. The perimeter is 28 inches. Find the length and the width \n" ); document.write( "
Algebra.Com's Answer #767905 by greenestamps(13200)\"\" \"About 
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\n" ); document.write( "(1) The perimeter is twice the length plus twice the width: \"P+=+2l%2B2w\"

\n" ); document.write( "(2) The length is 6 inches less than 3 times the width: \"l+=+3w-6\"

\n" ); document.write( "Substitute (2) in (1): \"P+=+2%283w-6%29%2B2w\"

\n" ); document.write( "(3) The perimeter is given as 28 inches: \"28+=+2%283w-6%29%2B2w\"

\n" ); document.write( "Solve that equation for the width w using basic algebra; then use (2) to find the length.

\n" ); document.write( "That's a good solution using formal algebra; and using the formal algebra to find the solution is good practice.

\n" ); document.write( "But if a formal algebraic solution is not required, guess and check is the fastest way to the answer. The perimeter is 28 inches, so length plus width is 14 inches.

\n" ); document.write( "Try combinations of length and width with a sum of 14 and find which pair satisfies the condition that the length is 6 less than 3 times the width:

\n" ); document.write( "1 and 13: 3(1)-6 = -3 nonsense
\n" ); document.write( "2 and 12: 3(2)-6 = 0 no...
\n" ); document.write( "3 and 11: 3(3)-6 = 3 no...
\n" ); document.write( "4 and 10: 3(4)-6 = 6 no...
\n" ); document.write( "5 and 9: 3(5)-6= 9 YES! DONE.
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