document.write( "Question 1146590: A ball is thrown from a height of 160 feet with an initial downward velocity of 12 ft/s. The bald height “h” (in feet) after “t” seconds is given by the following.
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document.write( "H=160-12t-16t^2
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document.write( "How long after the ball is thrown does it hit the ground?
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document.write( "Round to nearest hundredth \n" );
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Algebra.Com's Answer #767871 by Boreal(15235) You can put this solution on YOUR website! Hits ground when H=0 \n" ); document.write( "so -16t^2-12t+160=0 \n" ); document.write( "divide by 4 \n" ); document.write( "-4t^2-3t+40=0 \n" ); document.write( "4t^2+36-40=0 \n" ); document.write( "t=(1/8)(-3 +/- sqrt (9+640); sqrt 649=25.48 \n" ); document.write( "positive root only t=22.48/8=2.81 sec\r \n" ); document.write( "\n" ); document.write( " |