document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1146553>Question 1146553</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Suppose the population of a small town is 11000 and growing exponentially at 1.8 %. How many years until the population reaches 26000?\r<BR>\n" );
document.write( "<BR>\n" );
document.write( "<BR>\n" );
document.write( "<BR>\n" );
document.write( "<BR>\n" );
document.write( "\n" );
document.write( "Round to the nearest year. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #767866 by </B><A HREF=/tutors/aboutme.mpl?userid=Boreal><B>Boreal(15235)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Boreal><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Boreal><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=767866\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> P=Po(a^t)<BR>\n" );
document.write( "26000=11000(1.018)^t<BR>\n" );
document.write( "2.3636=1.018^t<BR>\n" );
document.write( "ln 2.3636=t ln 1.018 but carry all digits through and round at end\r<BR>\n" );
document.write( "\n" );
document.write( "t=ln 2.3636/ln 1.018<BR>\n" );
document.write( "=48.22 years or 48 years<BR>\n" );
document.write( "This is a little more than doubling, so rule of 72 would say a little more than 72/1.8=40. Answer makes sense. </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );