document.write( "Question 105451: A chemist has a 25% and a 50% acid solution. How much of each solution should be used to form 200 mL of a 35% acid solution?\r
\n" );
document.write( "\n" );
document.write( " \n" );
document.write( "
Algebra.Com's Answer #76782 by checkley75(3666)![]() ![]() ![]() You can put this solution on YOUR website! .50X+.25(200-X)=.35*200 \n" ); document.write( ".50X+50-.25X=70 \n" ); document.write( ".25X=70-50 \n" ); document.write( ".25X=20 \n" ); document.write( "X=20/.25 \n" ); document.write( "X=80 ML OF 50% SOLUTION. \n" ); document.write( "200-80=120 ML OF 30& SOLUTION. \n" ); document.write( "PROOF \n" ); document.write( ".50*80+.25*120=.35*200 \n" ); document.write( "40+30=70 \n" ); document.write( "70=70 \n" ); document.write( " |