document.write( "Question 105451: A chemist has a 25% and a 50% acid solution. How much of each solution should be used to form 200 mL of a 35% acid solution?\r
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Algebra.Com's Answer #76782 by checkley75(3666)\"\" \"About 
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.50X+.25(200-X)=.35*200
\n" ); document.write( ".50X+50-.25X=70
\n" ); document.write( ".25X=70-50
\n" ); document.write( ".25X=20
\n" ); document.write( "X=20/.25
\n" ); document.write( "X=80 ML OF 50% SOLUTION.
\n" ); document.write( "200-80=120 ML OF 30& SOLUTION.
\n" ); document.write( "PROOF
\n" ); document.write( ".50*80+.25*120=.35*200
\n" ); document.write( "40+30=70
\n" ); document.write( "70=70
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