document.write( "Question 1146493: snack mix A is 12% sodium and snack mix B is 4% sodium. we want to make a 40oz snack mix that is 9% sodium. how much of each snack mix is needed? \n" ); document.write( "
Algebra.Com's Answer #767771 by greenestamps(13203) You can put this solution on YOUR website! \n" ); document.write( "There are many ways to solve \"mixture\" problems like this, including using the ugly formula that the other tutor showed. \n" ); document.write( "But here is what is surely the fastest and easiest way.... \n" ); document.write( "(1) The 9% target percentage is 5/8 of the way from 4% to 12%, the percentages of the two ingredients. \n" ); document.write( "(2) That means 5/8 of the mixture is the higher percentage ingredient. \n" ); document.write( "ANSWER: 5/8 of 40 ounces, or 25 ounces, of the 12% sodium snack mix A; the other 15 ounces of snack mix B. \n" ); document.write( " |