document.write( "Question 105394: Solve each of the following systems by addition. If a unique solution does not exist, state whether the system is inconsistent or dependent.\r
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document.write( " 2x + 3y = 1
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document.write( "and 5x + 3y =16 \r
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document.write( "x+5y = 10
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document.write( "and -2x – 10y = -20 \n" );
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Algebra.Com's Answer #76772 by elima(1433)![]() ![]() ![]() You can put this solution on YOUR website! Solve each of the following systems by addition. If a unique solution does not exist, state whether the system is inconsistent or dependent.\r \n" ); document.write( "\n" ); document.write( "2x + 3y = 1 \n" ); document.write( "and 5x + 3y =16 \r \n" ); document.write( "\n" ); document.write( "x+ 5y = 10 \n" ); document.write( "and -2x – 10y = -20 \n" ); document.write( "================================= \n" ); document.write( "2x+3y=1 \n" ); document.write( "5x+3y=16 \n" ); document.write( "Multiply the first equation by -1; \n" ); document.write( "(-1)2x+3y =1 \n" ); document.write( "-2x-3y=-1 \n" ); document.write( "================ \n" ); document.write( "now add the equations; \n" ); document.write( "-2x-3y=-1 \n" ); document.write( "5x+3y=16 \n" ); document.write( "--------- \n" ); document.write( "3x=15 \n" ); document.write( "x=5 \n" ); document.write( "============== \n" ); document.write( "2(5)+3y=1 \n" ); document.write( "10+3y=1 \n" ); document.write( "3y=-9 \n" ); document.write( "y=-3 \n" ); document.write( "So this equation has a solution, it is independent \n" ); document.write( "=================================================== \n" ); document.write( "x+5y = 10 \n" ); document.write( "-2x – 10y = -20 \n" ); document.write( "===================== \n" ); document.write( "lets multiply the first equation by 2; \n" ); document.write( "(2)x+5y=10 \n" ); document.write( "2x+10y=20 \n" ); document.write( "=============== \n" ); document.write( "Now add the equations; \n" ); document.write( "2x+10y=20 \n" ); document.write( "-2x=10y=-20 \n" ); document.write( "------------ \n" ); document.write( "0=0 \n" ); document.write( "dependent \n" ); document.write( ":)\r \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |