document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1146445>Question 1146445</A>: <I><SPAN STYLE=\"word-break: break-all;\"> There is quite a pile of playing cards sitting at my house.<BR>\n" );
document.write( " A discovery I have made is as follows.<BR>\n" );
document.write( "if 2 people are playing cards one card will be leftover.<BR>\n" );
document.write( " if 3 people are playing cards 2 cards will be leftover.<BR>\n" );
document.write( "if 4 people are playing cards 3 cards will be leftover .<BR>\n" );
document.write( "if 5 people are playing cards for cards will be leftover.<BR>\n" );
document.write( " if 6 people are playing cards 5 cards will be leftover. <BR>\n" );
document.write( "if seven people are playing cards no cards will be leftover <BR>\n" );
document.write( "if I have the minimum amount of cards to satisfy the above conditions how many cards do I have? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #767706 by </B><A HREF=/tutors/aboutme.mpl?userid=Glaviolette><B>Glaviolette(140)</B></A><img src=\"/images/stars/stars-09.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Glaviolette><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Glaviolette><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=767706\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Since there are no cards left over when 5 or 7 people are playing, that means the number of cards is divisible by 5 and 7.  <BR>\n" );
document.write( "5 * 7 = 35<BR>\n" );
document.write( "35/2 = 17 r 1<BR>\n" );
document.write( "35/3 = 11 r 2<BR>\n" );
document.write( "35/4 = 8 r 3<BR>\n" );
document.write( "35/6 = 5 r 5\r<BR>\n" );
document.write( "\n" );
document.write( "Therefore, 35 is the minimum number of cards possible. </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );