document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1146450>Question 1146450</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The manager of a specialty food store combined almonds that cost $6.40 per pound with walnuts that<BR>\n" );
document.write( "cost $5.90 per pound. How many pounds of each were used to make a 100-pound mixture that costs<BR>\n" );
document.write( "$6.18 per pound? </SPAN>\n" );
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document.write( "Standard algebraic solution method....<br><BR>\n" );
document.write( "x pounds at $5.90 per pound, plus (100-x) pounds at $6.40 per pound, equals 100 pounds at $6.18 per pound:<br><BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=x%285.90%29%2B%28100-x%29%286.40%29+=+100%286.18%29 ALIGN=MIDDLE  ALT=\"x%285.90%29%2B%28100-x%29%286.40%29+=+100%286.18%29\"   DISABLED_style= \"max-width:90%; height:auto;\" ><br><BR>\n" );
document.write( "Straightforward; but some ugly calculations....<br><BR>\n" );
document.write( "A faster method, using only a couple of simple calculations, based on where the $6.18 per pound cost of the mixture lies between $5.90 and $6.40....<br><BR>\n" );
document.write( "(1) On a number line, look at where the 6.18 lies between 5.90 and 6.40.  5.90 to 6.40 is a difference of 0.50; 5.90 to 6.18 is a difference of 0.28.  0.28/0.50 = 28/50 = 56/100.<br><BR>\n" );
document.write( "(2) Therefore 56/100 of the mixture should be the higher priced walnuts.<br><BR>\n" );
document.write( "ANSWER: 56 pounds of the walnuts; 100-56 = 44 pounds of the almonds. </SPAN>\n" );
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