document.write( "Question 1146352: A chemist has 20% and 60% solutions of acid available. How many liters of each solution should be mixed to obtain 25 liters of 28% acid solution? \n" ); document.write( "
Algebra.Com's Answer #767629 by greenestamps(13200)\"\" \"About 
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\n" ); document.write( "Here is a faster and easier way to find the answer to \"mixture\" problems like this.

\n" ); document.write( "(1) The target 28% is 1/5 of the way from 20% to 60%. (20 to 60 is a difference of 40; 20 to 28 is a difference of 8; 8/40 = 1/5.)
\n" ); document.write( "(2) That means 1/5 of the mixture should be the higher (60%) ingredient.

\n" ); document.write( "ANSWER: 1/5 of 25L, or 5L, of 60% acid; the other 20L of 20% acid.
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