document.write( "Question 1146330: What rectangle has an area of 84ft and a perimiter of 40 \n" ); document.write( "
Algebra.Com's Answer #767603 by ankor@dixie-net.com(22740)\"\" \"About 
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What rectangle has an area of 84ft
\n" ); document.write( "L * w = 84
\n" ); document.write( " and a perimeter of 40
\n" ); document.write( "2L + 2w = 40
\n" ); document.write( "simplify, divide by 2
\n" ); document.write( "L + w = 20
\n" ); document.write( "L = (20-w)
\n" ); document.write( ":
\n" ); document.write( "in the first equation, replace L with (40-w)
\n" ); document.write( "(20-w) * w = 84
\n" ); document.write( "A quadratic equation
\n" ); document.write( "-w^2 + 20w - 84 = 0
\n" ); document.write( "Multiply by -1
\n" ); document.write( "w^2 - 20w + 84 = 0
\n" ); document.write( "Factors to
\n" ); document.write( "(w-6)(x-14) = 0
\n" ); document.write( "the smaller solution is the width
\n" ); document.write( "w = 6,
\n" ); document.write( "find L: 20-6 = 14 is the length
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