document.write( "Question 1146330: What rectangle has an area of 84ft and a perimiter of 40 \n" ); document.write( "
Algebra.Com's Answer #767603 by ankor@dixie-net.com(22740)![]() ![]() You can put this solution on YOUR website! What rectangle has an area of 84ft \n" ); document.write( "L * w = 84 \n" ); document.write( " and a perimeter of 40 \n" ); document.write( "2L + 2w = 40 \n" ); document.write( "simplify, divide by 2 \n" ); document.write( "L + w = 20 \n" ); document.write( "L = (20-w) \n" ); document.write( ": \n" ); document.write( "in the first equation, replace L with (40-w) \n" ); document.write( "(20-w) * w = 84 \n" ); document.write( "A quadratic equation \n" ); document.write( "-w^2 + 20w - 84 = 0 \n" ); document.write( "Multiply by -1 \n" ); document.write( "w^2 - 20w + 84 = 0 \n" ); document.write( "Factors to \n" ); document.write( "(w-6)(x-14) = 0 \n" ); document.write( "the smaller solution is the width \n" ); document.write( "w = 6, \n" ); document.write( "find L: 20-6 = 14 is the length \n" ); document.write( " \n" ); document.write( " |