document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1146289>Question 1146289</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Find the sum of 10 terms of the series log3+log6+log12+... given that log3 = 0.47741 and log2+0.3010 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #767564 by </B><A HREF=/tutors/aboutme.mpl?userid=greenestamps><B>greenestamps(13206)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=greenestamps><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=greenestamps><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=767564\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> <br><BR>\n" );
document.write( "log3+log6+log12+... (to 10 terms) =<BR>\n" );
document.write( "log3+log(3*2)+log(3*2^2)+...+log(3*2^9) =<BR>\n" );
document.write( "log3+(log3+log2)+(log3+log(2^2))+...+(log3+log(2^9)) =<BR>\n" );
document.write( "log3+(log3+log2)+(log3+2log2)+...+(log3+9log2) =<BR>\n" );
document.write( "10log3+(1+2+...+9)log2 =<BR>\n" );
document.write( "10log3+45log2 =<BR>\n" );
document.write( "10(0.47741)+45(0.3010) =<BR>\n" );
document.write( "4.7741+13.545 =<BR>\n" );
document.write( "18.3191 </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );