document.write( "Question 1146255: Five years ago, a boy was 1/5 as old as his father. thirteen years from now, the boy will be half as old as his father. find the present ages of the boy and his father. \n" ); document.write( "

Algebra.Com's Answer #767533 by ankor@dixie-net.com(22740) $\"\"$ $\"About$

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b = boys present age
\n" ); document.write( "f = father's
\n" ); document.write( ":
\n" ); document.write( "Write an equation for each statement, simplify
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\n" ); document.write( "Five years ago, a boy was 1/5 as old as his father.
\n" ); document.write( "b - 5 = $\"1%2F5\"$ (f-5)
\n" ); document.write( "multiply by 5, gets rid of the fraction
\n" ); document.write( "5(b-5) = f - 5
\n" ); document.write( "5b - 25 = f - 5
\n" ); document.write( "5b - 25 + 5 = f
\n" ); document.write( "5b - 20 = f
\n" ); document.write( ":
\n" ); document.write( " thirteen years from now, the boy will be half as old as his father.
\n" ); document.write( "b + 13 = $\"1%2F2\"$ (f + 13)
\n" ); document.write( "2(b + 13) = f + 13
\n" ); document.write( "2b + 26 - 13 = f
\n" ); document.write( "2b + 13 = f
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\n" ); document.write( " find the present ages of the boy and his father.
\n" ); document.write( "f = f, therefore
\n" ); document.write( "5b - 20 = 2b + 13
\n" ); document.write( "5b - 2b = 13 + 20
\n" ); document.write( "3b = 33
\n" ); document.write( "b = 11 yrs is the boy's age
\n" ); document.write( "Find father's age using f = 2b+ 13
\n" ); document.write( "f = 2(11) + 13
\n" ); document.write( "f = 35 yrs is fathers age
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\n" ); document.write( ":
\n" ); document.write( "Check in the statement:\"Five years ago, a boy was 1/5 as old as his father.\"
\n" ); document.write( "11 - 5 = $\"1%2F5\"$ (35-5)
\n" ); document.write( "6 = $\"1%2F5\"$ (30) \n" ); document.write( "

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