document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=105447>Question 105447</A>: <I><SPAN STYLE=\"word-break: break-all;\"> You role a six sided die 30 times.  What is the theoretical probability of rolling a 1? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #76753 by </B><A HREF=/tutors/aboutme.mpl?userid=checkley75><B>checkley75(3666)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=checkley75><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=76753\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> I BELIEVE THE FORMULA IS P=1-(5/6)^30<BR>\n" );
document.write( "IT WORKS FOR THE FIRST ROLL<BR>\n" );
document.write( "P=1-(5/6)^1<BR>\n" );
document.write( "P=1-5/6<BR>\n" );
document.write( "P=1/6<BR>\n" );
document.write( "P=.1666<BR>\n" );
document.write( "FOR THE SECOND ROLL<BR>\n" );
document.write( "P=1-(5/6)^2<BR>\n" );
document.write( "P=1-(25/36)<BR>\n" );
document.write( "P=1-.69<BR>\n" );
document.write( "P=.31<BR>\n" );
document.write( "THE MORE ROLLS THE HIGHER THE PROBABILITY OF ROLLING A 1.<BR>\n" );
document.write( "THE PROBABILITY APPROACHES 1 OR 100%. </SPAN>\n" );
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