document.write( "Question 1146228: peter leaves his house at 6:45 am and drives east. At 7:15 am, Paul leaves his house driving east. Paul's speed is 25 mph faster than half peters speed. At 7:35 am, they pass each other on the road. Find Pauls speed if they live 59.3 miles apart. \n" ); document.write( "
Algebra.Com's Answer #767524 by ankor@dixie-net.com(22740)![]() ![]() You can put this solution on YOUR website! Does not really make sense as written, lets change it to Paul driving west (toward each other) \n" ); document.write( ": \n" ); document.write( " peter leaves his house at 6:45 am and drives east. \n" ); document.write( " At 7:15 am, Paul leaves his house driving west. \n" ); document.write( " Paul's speed is 25 mph faster than half peters speed. \n" ); document.write( " At 7:35 am, they pass each other on the road. \n" ); document.write( " Find Pauls speed if they live 59.3 miles apart. \n" ); document.write( ": \n" ); document.write( "let x = Peter's speed \n" ); document.write( "then \n" ); document.write( "(.5x+25) = Paul's speed \n" ); document.write( ": \n" ); document.write( "6:45 to 7:35 = 50 min is Peter's travel time (.8333 hr) \n" ); document.write( "and \n" ); document.write( "7:15 to 7:35 = 20 min is Paul's travel time (.3333 hr) \n" ); document.write( ": \n" ); document.write( "When they meet, the sum of their distances = 59.3 mi \n" ); document.write( "Write a dist equation; dist = speed (mph) * time (hr) \n" ); document.write( ": \n" ); document.write( "Peter's dist + Paul's dist = 59.3 mi \n" ); document.write( ".8333x + .333(.5x+25) = 59.3 \n" ); document.write( ".8333x + .1665x + 8.325 = 59.3 \n" ); document.write( ".9998x = 59.3 - 8.325 \n" ); document.write( "close enough to 1 \n" ); document.write( "x = 50.975 ~ 51 mph is Peter's speed \n" ); document.write( "then \n" ); document.write( ".5(50.975) + 25 = 50.4875 ~ 50.5 mph is Paul's speed \n" ); document.write( ": \n" ); document.write( "Seems the are going about the same speed, see if this checks out \n" ); document.write( ".8333(51) = 42.5 mi \n" ); document.write( ".3333(50.5) = 16.8 mi \n" ); document.write( "--------------------- \n" ); document.write( "total distance 59.3 m \n" ); document.write( ": \n" ); document.write( ": \n" ); document.write( "A rather strange problem! \n" ); document.write( " |